The Answer Is Not 0.5

Algebra Level 5

What is the smallest real number kk (to 3 decimal places), such that for all ordered triples of non-negative reals (a,b,c) (a,b,c) which satisfy a+b+c=1 a + b + c = 1 , we have

a2+bca+1+b2+cab+1+c2+abc+1k? \frac{ a^2 + bc} { a+1} + \frac{ b^2+ca} { b+1} + \frac{ c^2+ab} { c+1} \leq k?


If you want a similar inequality, you can try The Answer Is Not 0.225.

×

Problem Loading...

Note Loading...

Set Loading...