Given a Set \(A=\{b,r,i,l,a,n,t\}\). Then the number of ordered pairs \((P,Q,R,S)\) which can be formed such that \(P \subseteq A\) , \(Q \subseteq A\), \(R \subseteq A\), \(S \subseteq A\) And \((P\cup Q)\cap (R\cup S)=\emptyset \).

- The answer is of the form \(m^{n}\) where \(m,n\) are primes. Find \(m+n\)

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