JEE ADV -2013 (Paragraph questions 13-14). The problem was quite easy because work done by friction had been given and conservation of energy could be easily applied. I tried to find out how the work done by friction is evaluated.This try led to the formation of the following problem:

This problem has been inspired by a problem appearing in theConsider a fixed wedge, whose part is a quarter circle of radius \(R\) as shown. A small block of mass \(m\) slides down the wedge and leaves horizontally from a height \(h\) as shown.The coefficient of friction between wedge and block is \(\mu_{k}\). Compute the value of \(x\) in **centimetres** , where \(x\) is the distance from bottom of wedge of the point where the block falls given the values below:

**Details**

\(R = 200 cm\)

\(h = 105 cm\)

\(\mu_{k} = 0.5\)

\(m = 2g\)

**Round your answer to nearest integer**

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