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How many possible 6 digit numbers are there of the form N=abcabd‾ N=\overline{abcabd} N=abcabd where a≠0,d≠0 a \neq 0, d \neq 0a=0,d=0, d=c+1d = c + 1 d=c+1 and N N N is a perfect square?
Details and assumptions
The condition of a≠0a \neq 0 a=0 follows because we have a 6 digit number. The condition of d≠0 d \neq 0 d=0 follows because 0≠9+1 0 \neq 9 + 1 0=9+1.
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