The Easy Peasy Sum of Series Part 3

Calculus Level 3

The following summation of series n=0n33n\sum_{n=0}^\infty\frac{n^{\large 3}}{3^{\large n}} equals mn\dfrac{m}{n}. Compute m+n\large m+n.


Note :

Please provide the solution if you can answer it. Also, you may use Wolfram Alpha, but will you do that??? It's up to you. (>‿◠)✌

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