\[\LARGE n¡=n^{{(n-1)}^{{(n-2)}^{.^{.^{.^{2^{\small1}}}}}}}\]

If \(n¡\) is defined as above, what are the last **two** digits of the number \(2018¡?\)

**Note:** \(\large ¡\) is the factorial notation \(!\) turned upside down. Note that \(\large ¡\) keeps exponentiating while \(!\) keeps multiplying.

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