The Exponentorial of 20182018

n¡=n(n1)(n2)...21\LARGE n¡=n^{{(n-1)}^{{(n-2)}^{.^{.^{.^{2^{\small1}}}}}}}

If n¡ is defined as above, what are the last two digits of the number 2018¡?2018¡?

Note: ¡\large ¡ is the factorial notation !! turned upside down. Note that ¡\large ¡ keeps exponentiating while !! keeps multiplying.

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