# The Exponentorial of $$2018$$

Define $$n¡$$ to be $\LARGE n¡=n^{{(n-1)}^{{(n-2)}^{.^{.^{.^{2^{\small1}}}}}}}.$ What are the last two digits of the number $$2018¡?$$

Note: $$\large ¡$$ is the factorial notation $$!$$ turned upside down. Note that $$\large ¡$$ keeps exponentiating while $$!$$ keeps multiplying.

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