# The Exponentorial of $2018$

$\LARGE n¡=n^{{(n-1)}^{{(n-2)}^{.^{.^{.^{2^{\small1}}}}}}}$

If $n¡$ is defined as above, what are the last two digits of the number $2018¡?$

Note: $\large ¡$ is the factorial notation $!$ turned upside down. Note that $\large ¡$ keeps exponentiating while $!$ keeps multiplying.

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