The famous factorial again!

12!9!+13!8!+14!7!+15!6!=n10!,n= ?  \large \dfrac1{2!9!}+\dfrac1{3!8!}+\dfrac1{4!7!}+\dfrac1{5!6!}=\dfrac n{10!} \quad,\quad n= \ ? \

×

Problem Loading...

Note Loading...

Set Loading...