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(4+15)3/2+(4−15)3/2(6+35)3/2−(6−35)3/2.\dfrac{(4+\sqrt{15})^{3/2}+(4-\sqrt{15})^{3/2}}{(6+\sqrt{35})^{3/2}-(6-\sqrt{35})^{3/2}}.(6+35)3/2−(6−35)3/2(4+15)3/2+(4−15)3/2.If the value of above surd is equal to ab\dfrac{a}{b}ba,where gcd(a,b)=1\text{gcd}(a,b)=1gcd(a,b)=1, find a+b.a+b.a+b.
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