The Internal Angle Bisector

Geometry Level 3

In ABC\triangle ABC, ABC=30°.\angle ABC = 30°. Points PP and QQ are chosen on AC\overline{AC} such that AP+BC=AB+CQAP+BC= AB+CQ. The internal angle bisector of ABC\angle ABC intersects AC\overline{AC} at RR.

Given that RR is the midpoint of PQPQ, find BAC\angle BAC (in degrees).


This problem has been adapted from the Proofathon Geometry contest, and was posed by Shivang Jindal.
×

Problem Loading...

Note Loading...

Set Loading...