As shown below, the last digit of $n!$ for each of $n=5, 6, 7$ is zero:
$5!=12{\color{#D61F06}0},\quad 6!=72{\color{#D61F06}0},\quad 7!=504{\color{#D61F06}0}.$
Is it true that the last digit of $n!$ is zero for all positive integers $n>4?$

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