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Given that E=a3−b3−c3−3abca2+b2+c2+ab−bc+ac \mathscr{E} = \dfrac{a^3 -b^3 -c^3 - 3abc}{a^2 + b^2 + c^2 + ab - bc + ac} E=a2+b2+c2+ab−bc+aca3−b3−c3−3abc
and a=2015,b=2016,c=2017 a = 2015, b = 2016, c = 2017 a=2015,b=2016,c=2017. Find E \mathscr{E}E.
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