# The Vector Jogger

**Calculus**Level 2

A jogger is jogging around a circular park of radius 1 kilometer at a speed of 6.28 kilometers per hour. The jogger starts at some point \(A\), and jogs around the park to a point \(B\), diametrically opposite to \(A\). During his jog, how many minutes after starting from \(A\), does the ratio between the jogger's distance and the jogger's displacement reach a maximum?

**Details:**

Take \(\pi\approx 3.14\)

The ratio to be maximized is \(\frac{Distance}{Displacement}\)