There should a limit somewhere

Calculus Level 2

True or False?

1+2+3+4+5+6+2+4+6+8+10+12+=12 \dfrac{1 + 2 + 3 +4 + 5 + 6+ \cdots } {2 + 4 + 6 + 8 + 10 + 12 + \cdots } = \dfrac12

×

Problem Loading...

Note Loading...

Set Loading...