A physicist went into the kitchen. He wanted to make a cup of tea so the first thing he does is opens the kettle and he thinks "I wonder how strong the current in the wire is that's being used to boil the water?" So he puts \(\SI{250}{\gram}\) of water into the kettle and finds that it takes 1 minute 35 seconds to heat the water to \(\SI{100}{\celsius}\).

Can you calculate the current in the wire?

**Details and Assumptions**:

- No heat energy is lost to the surrounding.
- All heat energy from the wire is given to the water.
- \(C\) (the specific heat capacity of water) is equal to \(4.2\textrm{ J/g C}\).
- Voltage from the wall is \(230\text{ V}\).
- The initial temperature of the water is zero but not frozen.

Give your answer to 3 decimal places.

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