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f(x)=∫dx(x+2)4+(x+4)4+14\large{ f(x) = \int \dfrac{dx}{(x+2)^4 + (x+4)^4 + 14} }f(x)=∫(x+2)4+(x+4)4+14dx
Let f(x)f(x)f(x) be a function defined as above such that f(−3)=0f(-3) = 0f(−3)=0 holds true. Then find the value of f(0)f(0)f(0) upto three decimal places.
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