# Recurring Dreams!

**Algebra**Level 5

\[\large{{ y }_{ n+1 }=10\left\lfloor \sqrt { 4{ y }_{ n }-3 } \right\rfloor }\]

If there be a sequence defined by above rule for \(n \ge 1\). Find \(y_{2015}\) if \(y_{1}=9000\)

\[\large{{ y }_{ n+1 }=10\left\lfloor \sqrt { 4{ y }_{ n }-3 } \right\rfloor }\]

If there be a sequence defined by above rule for \(n \ge 1\). Find \(y_{2015}\) if \(y_{1}=9000\)

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