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4+12+11+13+11+12+18+1⋱=A\Large 4+\frac{1}{2+\frac{1}{1+\frac{1}{3+\frac{1}{1+\frac{1}{2+\frac{1}{8+\frac{1}{\ddots} } } } } } } = \sqrt{ A} 4+2+1+3+1+2+8+⋱1111111=A
Find the positive integer AAA in the equation above.
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