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Let f(x)=x2014+2014x\displaystyle f(x) = x^{2014}+2014^xf(x)=x2014+2014x.
Find ∫12015f−1(x) dx.\displaystyle \int_{1}^{2015} f^{-1} (x) \, {\mathrm{dx}}.∫12015f−1(x)dx.
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