# This made me won

Algebra Level 1

Let $$x, y$$, and $$z$$ be real numbers such that
$$x+y+z=6$$ and
$$\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z}=2$$.. Find the value of
$$\dfrac{(x+y)}{z}+\dfrac{(y+z)}{x}+\dfrac{(x+z)}{y}$$.

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