# This made me won

**Algebra**Level 1

\( x+y+z=6\) and

\( \dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z}=2 \).. Find the value of

\( \dfrac{(x+y)}{z}+\dfrac{(y+z)}{x}+\dfrac{(x+z)}{y}\).

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