This made me won

Algebra Level 1

Let \(x, y\), and \(z\) be real numbers such that
\( x+y+z=6\) and
\( \dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z}=2 \).. Find the value of
\( \dfrac{(x+y)}{z}+\dfrac{(y+z)}{x}+\dfrac{(x+z)}{y}\).

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