# This should be easy! Right? Part - 2

Geometry Level 5

In a quadrilateral $$ABCD$$, $$AB = 6$$ $$cm$$, $$\cos \angle ADB = \frac{7}{8}$$, $$\sin \angle BDC = \frac{\sqrt{15}}{8}$$, $$\cos \angle DCA = \frac{11}{16}$$ and $$\sin \angle ACB = \frac{\sqrt{15}}{8}$$.

Find $$CD$$ (in $$\text{cm}$$).

Try Part-1 and Part-3 also.

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