This should be easy! Right? Part - 2

Geometry Level 5

In a quadrilateral \(ABCD\), \(AB = 6\) \(cm\), \(\cos \angle ADB = \frac{7}{8}\), \(\sin \angle BDC = \frac{\sqrt{15}}{8}\), \(\cos \angle DCA = \frac{11}{16}\) and \(\sin \angle ACB = \frac{\sqrt{15}}{8}\).

Find \(CD\) (in \(\text{cm}\)).

Try Part-1 and Part-3 also.

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