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THREETHREETWOTWO+ONEELEVEN\large \begin{array} {c c c c c c } & T &H & R & E & E \\ & T & H & R & E & E \\ & & & T &W & O\\ & & & T &W &O\\ + & & & O &N & E \\ \hline E & L & E & V & E & N \\ \hline \end{array} +ETTLHHERRTTOVEEWWNEEEOOEN
In the above cryptarithm, find the value of ELEVEN‾\overline{ELEVEN}ELEVEN.
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