$3+3+2+2+1=11$

Logic

$\large \begin{array} {c c c c c c } & T &H & R & E & E \\ & T & H & R & E & E \\ & & & T &W & O\\ & & & T &W &O\\ + & & & O &N & E \\ \hline E & L & E & V & E & N \\ \hline \end{array}$

In the above cryptarithm, find the value of $\overline{ELEVEN}$ .

$T$ , $H$ , $R$ , $E$ , $W$ , $O$ , $N$ , $L$ and $V$ represent distinct single digit non-negative integers, and $T,E$ and $O$ are non-zero.

3+3+2+2+1=113+3+2+2+1=113+3+2+2+1=11

$3+3+2+2+1=11$