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1a×1b=1a×b\frac1a\times\frac1b=\frac1{a\times b}a1×b1=a×b1
Knowing the above, can we also say there are real numbers aaa and bbb such that 1a+1b=1a+b?\frac1a+\frac1b=\frac1{a+b}?a1+b1=a+b1?
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