Not-so-simple harmonic motion

A pendulum has length \(l=\SI{30}{\centi\meter}\) and a bob of mass \(m=\SI{2}{\kilo\gram}\). At time zero, the mass is brought \(\theta=\SI{90}{\degree}\) from which it is released, with zero initial velocity.

Find the time \(\Delta t\) in seconds to reach the bob to the opposite end (left end).

Details

  • \(g=\SI[per-mode=symbol]{10}{\meter\per\second\squared}\) .
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