# Not-so-simple harmonic motion

A pendulum has length $$l=\SI{30}{\centi\meter}$$ and a bob of mass $$m=\SI{2}{\kilo\gram}$$. At time zero, the mass is brought $$\theta=\SI{90}{\degree}$$ from which it is released, with zero initial velocity.

Find the time $$\Delta t$$ in seconds to reach the bob to the opposite end (left end).

Details

• $$g=\SI[per-mode=symbol]{10}{\meter\per\second\squared}$$ .
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