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Given that f(2x−3)=f(2x)+1f(2x)−1f(2x-3)=\dfrac{f(2x)+1}{f(2x)-1}f(2x−3)=f(2x)−1f(2x)+1 and f(7)=5f(7) = 5f(7)=5, find f(10)f(4)\dfrac{f(10)}{f(4)}f(4)f(10).
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