Too many Fractions and too much Infinity!

Algebra Level 4

3(n=4(limx+1+2+3+...+xx2)2n)5=ab\frac{3(\sum\limits_{n=4}^\infty \frac{(\lim_{x \to +\infty} \frac{1+2+3+...+x}{x ^ 2})}{2 ^ n})}{5}=\frac{a}{b}

gcd(a,b)=1gcd(a, b)=1

ab1=xab-1=x

What is the value of xx?

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