Trailing Zeroes

Given that 13!=13×12×11××2×1=622702080013!= 13 \times 12 \times 11 \times \cdot \cdot \cdot \times 2 \times 1 = 6227020800 , it can be seen that 13!13! contains two trailing zeroes.

How many trailing zeroes does 1000!1000! contain?

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