Triangle, Circles, Angles

Level pending

$$BC$$ is the diameter of a semi-circle. The sides of $$AB$$ and $$AC$$ of a triangle $$ABC$$ meet the semi-circle in $$P$$ and $$Q$$ respectively. $$PQ$$ subtends $$140^\circ$$ at the centre of the semi-circle. Then $$\angle A$$ is equal to:

(A) $$10^\circ$$.
(B) $$20^\circ$$.
(C) $$30^\circ$$.
(D) $$40^\circ$$.

×