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\(BC\) is the diameter of a semi-circle. The sides of \(AB\) and \(AC\) of a triangle \(ABC\) meet the semi-circle in \(P \) and \(Q\) respectively. \(PQ\) subtends \(140^\circ\) at the centre of the semi-circle. Then \(\angle A \) is equal to:

(A) \(10^\circ\).

(B) \(20^\circ\).

(C) \(30^\circ\).

(D) \(40^\circ\).

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