Triangle, Circles, Angles

Level pending

\(BC\) is the diameter of a semi-circle. The sides of \(AB\) and \(AC\) of a triangle \(ABC\) meet the semi-circle in \(P \) and \(Q\) respectively. \(PQ\) subtends \(140^\circ\) at the centre of the semi-circle. Then \(\angle A \) is equal to:

(A) \(10^\circ\).
(B) \(20^\circ\).
(C) \(30^\circ\).
(D) \(40^\circ\).

×

Problem Loading...

Note Loading...

Set Loading...