# Triangle Tip

**Geometry**Level pending

In a triangle \(ABC\), \(x+y+2=0\) is the perpendicular bisector of side \(AB\) and it meets AB at \((-1,-1)\). If \( x-y-1=0 \) is the perpendicular bisector of side \(AC\) and it meets \(AC\) at \((2,1)\) and \(P\) is the mid point of \( BC \) then distance of \(p\) from orthocentre of triangle \( ABC\) is: