# Triangle Tip

Geometry Level pending

In a triangle $$ABC$$, $$x+y+2=0$$ is the perpendicular bisector of side $$AB$$ and it meets AB at $$(-1,-1)$$. If $$x-y-1=0$$ is the perpendicular bisector of side $$AC$$ and it meets $$AC$$ at $$(2,1)$$ and $$P$$ is the mid point of $$BC$$ then distance of $$p$$ from orthocentre of triangle $$ABC$$ is:

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