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In a right triangle, find the measure of angle θ \theta θ between the median and the angle bisector drawn from the vertex of the acute angle equal to α \alpha α.
Now, if tan(α2)=123 \tan\left(\dfrac{\alpha}{2}\right) = \dfrac{1}{\sqrt[3]{2}} tan(2α)=321, enter tan(θ) \tan(\theta) tan(θ) as your answer.
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