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{3sinA+4cosB=63cosA+4sinB=1 \large \begin{cases}{3\sin A + 4\cos B = 6} \\ {3\cos A + 4\sin B = 1}\end{cases} ⎩⎨⎧3sinA+4cosB=63cosA+4sinB=1
In a triangle ABCABCABC, we are given that two angles A,BA,BA,B satisfy the equation above, find the measure of the remaining angle, CCC (in degrees).
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