Trignometry - 6

Geometry Level 4

sin(A)sin(2A)sin(3A)sin(4A)=ax2+bx3+cx4+dx5 \sin (A) \sin(2A) \sin(3A) \sin(4A) = ax^2 + bx^3 + cx^4 + dx^5

If sin2(A)=x \sin^{2}(A)= x and that the equation above is satisfied for constants a,b,c,da,b,c,d, then find the value of 12a10b+8c11d 12a - 10b +8c -11d .

×

Problem Loading...

Note Loading...

Set Loading...