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{x=asec3β tanβy=btan3β secβ\large \begin{cases} x = a \sec^3 \beta \ \tan \beta \\ y = b \tan^3 \beta \ \sec \beta \end{cases} ⎩⎨⎧x=asec3β tanβy=btan3β secβ
Given the above, find sin2β\sin^2 \betasin2β.
Details and assumptions:
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