# Trigonometry! #128

Geometry Level 2

The area of a cyclic $$\Box ABCD$$ is $$\frac{3\sqrt{3}}{4}$$. The radius of the circle circumscribing it is $$1$$. If $$AB=1$$ and $$BD=\sqrt{3}$$, evaluate $$BC\cdot CD$$.

This problem is part of the set Trigonometry.

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