Trigonometry! #128

Geometry Level 2

The area of a cyclic \(\Box ABCD\) is \(\frac{3\sqrt{3}}{4}\). The radius of the circle circumscribing it is \(1\). If \(AB=1\) and \(BD=\sqrt{3}\), evaluate \(BC\cdot CD\).

This problem is part of the set Trigonometry.

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