Trigonometry #129

Geometry Level 2

Select the equivalent of

(1sec2αcos2α+1csc2αsin2α)cos2αsin2α.\left(\frac{1}{\sec^{2}\alpha-\cos^{2}\alpha}+\frac{1}{\csc^{2}\alpha-\sin^{2}\alpha}\right)\cdot\cos^{2}\alpha\sin^{2}\alpha.


This problem is part of the set Trigonometry.

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