Trigonometry #129

Geometry

Select the equivalent of

$\left(\frac{1}{\sec^{2}\alpha-\cos^{2}\alpha}+\frac{1}{\csc^{2}\alpha-\sin^{2}\alpha}\right)\cdot\cos^{2}\alpha\sin^{2}\alpha.$

This problem is part of the set Trigonometry.

\frac{1-\cos^{2}\alpha\sin^{2}\alpha}{2-\cos^{2}\alpha\sin^{2}\alpha}

\frac{1+\cos^{2}\alpha\sin^{2}\alpha}{2-\cos^{2}\alpha\sin^{2}\alpha}

\frac{1+\cos^{2}\alpha\sin^{2}\alpha}{2+\cos^{2}\alpha\sin^{2}\alpha}

\frac{1-\cos^{2}\alpha\sin^{2}\alpha}{2+\cos^{2}\alpha\sin^{2}\alpha}