Trigonometry #129

Geometry Level 2

Select the equivalent of

\[\left(\frac{1}{\sec^{2}\alpha-\cos^{2}\alpha}+\frac{1}{\csc^{2}\alpha-\sin^{2}\alpha}\right)\cdot\cos^{2}\alpha\sin^{2}\alpha.\]

This problem is part of the set Trigonometry.

\[\frac{1+\cos^{2}\alpha\sin^{2}\alpha}{2+\cos^{2}\alpha\sin^{2}\alpha}\] \[\frac{1+\cos^{2}\alpha\sin^{2}\alpha}{2-\cos^{2}\alpha\sin^{2}\alpha}\] \[\frac{1-\cos^{2}\alpha\sin^{2}\alpha}{2-\cos^{2}\alpha\sin^{2}\alpha}\] \[\frac{1-\cos^{2}\alpha\sin^{2}\alpha}{2+\cos^{2}\alpha\sin^{2}\alpha}\]

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