# Trigonometry! #155

Geometry Level 3

In $$\Delta ABC$$, $$\angle B=60^{\circ}$$ and $$\angle C=45^{\circ}$$. Let $$D$$ divide $$BC$$ internally in the ratio $$1:3$$. Then find the value of $\frac{\sin\angle BAD}{\sin\angle CAD}$

Express your answer in the form of $$\frac{a}{b}$$, where $$a$$ and $$b$$ have nothing in common. Enter the value of $$a^{2}+b^{2}$$.

This problem is part of the set Trigonometry.

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