The solution set of ∣4sin(x)−1∣<5 for ∣x∣<π is
Options:
(−π,−54π)∪(−5π,10π)∪(109π,π)
(−109π,−10π)∪(103π,107π)
(−π,−109π)∪(−10π,103π)∪(107π,π)
(−107π,109π)
Note: Enter the serial number of the correct option.
This problem is part of the set Trigonometry.