In \(\Delta ABC\), \(A=20^{\circ}\), \(B=C=80^{\circ}\). \(D\) lies on \(\overline{AC}\) such that \(m\angle DBC = 70^{\circ}\). \(E\) lies on \(\overline{AB}\) such that \(m\angle ECB = 50^{\circ}\). Enter the measure of \(\angle BDE\) in degrees, without the degree sign.

**Bonus**: Solve this problem by Ceva's theorem.

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