Trigonometry! #99

Geometry Level 2

For all $0 < \theta < 90^\circ,$

$\sqrt{\sec^{2}\theta+\csc^{2}\theta}=\, ?$

\tan\theta+\cot\theta

\frac{\sec^{2}\theta}{\csc^{2}\theta}

\sec\theta-\tan\theta

\sec\theta+\csc\theta