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Trigonometry! #99

Geometry Level 2

For all \(0 < \theta < 90^\circ,\)

\[\sqrt{\sec^{2}\theta+\csc^{2}\theta}=\, ?\]

\[\frac{\sec^{2}\theta}{\csc^{2}\theta}\] \[\tan\theta+\cot\theta\] \[\sec\theta-\tan\theta\] \[\sec\theta+\csc\theta\]

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by Omkar Kulkarni

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