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Trigonometry! #99

Geometry Level 2

For all $0 < \theta < 90^\circ,$

$\sqrt{\sec^{2}\theta+\csc^{2}\theta}=\, ?$

\frac{\sec^{2}\theta}{\csc^{2}\theta}

\tan\theta+\cot\theta

\sec\theta-\tan\theta

\sec\theta+\csc\theta

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Excel in math and science

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by Omkar Kulkarni

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