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Trigonometry expression

Geometry Level 1

\[\tan{\theta}\]

Which identity is equal to the above expression?

\[\text{}1-{\cos}^{2}{\theta}\] \[\frac{\cos{\theta}}{\sin{\theta}}\] \[\text{}{\cos}^{2}{\theta}+{\sin}^{2}{\theta}\] \[\frac{\sin{\theta}}{\cos{\theta}}\] \[\text{}1-{\sin}^{2}{\theta}\]

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by Matin Naseri

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