Trigonometry II

Geometry Level 3

α=(3+tan⁡(1∘)).((3+tan⁡(2∘))...((3+tan⁡(29∘))\displaystyle \alpha = (\sqrt{3} + \tan (1^\circ)).((\sqrt{3} +\tan(2^\circ))...((\sqrt{3}+\tan(29^\circ))

What Is The Last Three Digits of α\alpha ?

Details :

  • Is Product Tan 1∘1^\circ Until 29∘29^\circ

  • You Can Use A Calculator

Gabriel Merces by Gabriel Merces
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