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α=(3+tan(1∘)).((3+tan(2∘))...((3+tan(29∘))\displaystyle \alpha = (\sqrt{3} + \tan (1^\circ)).((\sqrt{3} +\tan(2^\circ))...((\sqrt{3}+\tan(29^\circ))α=(3+tan(1∘)).((3+tan(2∘))...((3+tan(29∘))
What Is The Last Three Digits of α\alphaα ?
Details :
Is Product Tan 1∘1^\circ1∘ Until 29∘29^\circ29∘
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