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8x3−6x+1=0\large 8x^3-6x+1 = 08x3−6x+1=0
If aaa, bbb and ccc are the roots of the equation above, find the value of cos−1a+cos−1b+cos−1c\cos^{-1} a + \cos^{-1} b + \cos^{-1} ccos−1a+cos−1b+cos−1c in degrees.
If you think that roots exist outside [−1,1][-1, 1][−1,1], write 272 as your answer.
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