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ABCDABCDABCD is a square with area 720 720 720. Points E,F,G,HE, F, G, H E,F,G,H trisect the sides of the square, such that AEEB=BFFC=CGGD=DHHA=2 \frac{ AE}{EB} = \frac{ BF}{FC} = \frac{ CG}{GD} = \frac{DH}{HA} = 2 EBAE=FCBF=GDCG=HADH=2. What is the area of square EFGH EFGH EFGH?
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