# Trisected square

Geometry Level 2

$ABCD$ is a square with area $720$. Points $E, F, G, H$ trisect the sides of the square, such that $\frac{ AE}{EB} = \frac{ BF}{FC} = \frac{ CG}{GD} = \frac{DH}{HA} = 2$. What is the area of square $EFGH$?

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