Forgot password? New user? Sign up
Existing user? Log in
Given that
sinθ+sin2θ+sin3θ=1, \sin \theta + \sin^2 \theta + \sin^3 \theta = 1, sinθ+sin2θ+sin3θ=1,
find the value of
cos6θ−4cos4θ+8cos2θ \cos^6 \theta - 4 \cos^4 \theta + 8 \cos ^2 \theta cos6θ−4cos4θ+8cos2θ
Please share your solution. I am really confused about this problem.
Problem Loading...
Note Loading...
Set Loading...