# Well, just apply induction

Algebra Level 2

$\large \displaystyle\sum_{r=1}^n r = \dfrac{n(n+1)}{2}$

It is well known that the formula for the sum of the first $$n$$ natural numbers is given as above. Keeping in mind of the formula stated above, is the summation below true?

$\large\displaystyle\sum_{r=1}^n (r+1) = \dfrac{(n+1)(n+2)}{2}$

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