# True or True #10

**Algebra**Level 3

*real number* and \[\sqrt{ax + b} = -cx-d\] has a solution such that \[0<c<a\] then \[x < -\dfrac{b+d}{a+c}\]

*real number* and \[\sqrt{ax + b} = -cx-d\] has a solution such that \[0<c<a\] then \[x < -\dfrac{b+d}{a+c}\]

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