# Truncate The Square

Does there exist a positive integer $$n$$ and digits $$a_1 \neq 0, a_2, \ldots, a_n$$ such that

$\sqrt{ \overline{a_1 a_2 \ldots a_{n-1} a_n }} - \sqrt{ \overline{a_1 a_2\ldots a_{n-1} } } = a_n ?$

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