Two faulty analog clocks are set correctly at midnight, one that gains a *x* number of minutes (under 50 minutes) every hour, and one that loses a *y* number of minutes (under 50 minutes) every hour. At 6:00 PM (real time) the same day, they will both read the same time. The next time the clock that gains minutes "thinks" it is midnight, the other clock will read "1:20". Find \(3x + 2y\).

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