A ball with mass $m$ is thrown from the origin at speed $V_{0}$ toward the right on an exotic planet where the strength of gravity is $g^\prime = \frac{g}{10} = \SI[per-mode=symbol]{1}{\meter\per\second\squared}.$

Let $\alpha$ be the largest possible angle such that, for all $\theta<\alpha$, the distance between the ball and its launch point will be strictly increasing for $t>0$.

What is $\tan^{2} \alpha,$ to two decimal places?

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**Details and Assumptions:**

- $V_{0}=100 \text{ m/s}.$
- $m=1 \text{ kg}.$

**Bonus:** Generalize this angle for arbitrary values of $V_{0}$, $m$, and $g^\prime$.

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