Use the basics

Find the sum of all positive integers \(d\) such that

\(d\mid(n^2+1)\)

\(d\mid[(n+1)^2+1]\)

Details & Assumptions

\(\bullet\) \(n\) is a non-negative integer

\(\bullet\) \(a \mid b\) means "\(a\) divides \(b\)" i.e. \(b\) is divisible by \(a\).

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