The Recursion Is Trapped In The Exponent!

Calculus Level 1

The sequence {an}\{ {a}_{n}\} satisfies (2n+12n1)an=e2. \left(\frac{2n+1}{2n-1}\right)^{a_n} =e^2. Find limn2ann+1 \lim_{n \rightarrow \infty}\frac{2a_n}{n+1} .

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